Let g(x)= 1/(sqr(x-6)) . Evaluate the expression (g(x)- g(10))/(x-10) and then simplify the result. *sqr= square root
what is g(10)?
It;s just g(10). I think the whole expression is for limits, but I can't figure out how to do this.
\[g(x) = \frac{1}{\sqrt{x-6}}\\g(10) = \frac{1}{\sqrt{10-6}}=\frac{1}{2}\]you need \[\frac{g(x)-g(10)}{x-10}=\frac{\frac{1}{\sqrt{x-6}}-\frac{1}{2}}{x-10}=\frac{\frac{2-\sqrt{x-6}}{2(x-6)}}{x-10}=\frac{2-\sqrt{x-6}}{2(x-10)(x-6)}\]
im not sure what you want to do here...
You just need to simplify it. And how did you get (x-6)? Wouldn't it still be \[\sqrt{x-6}\]? Not only do we both have different answers, but both are not one of the MC answers.
yes it should be sqrt sorry. i hate latex... \[\frac{2-\sqrt{x-6}}{2\sqrt{x-6}(x-10)}\]
Nevermind I got the right answer now! I just had to multiply everything out by \[\sqrt{x-6}\] so that the bottom would no longer be radical :p!
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