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|dw:1377671228491:dw|
@dumbcow
@mathslover
\[c \int\limits _0 ^\infty e^{-3x} dx = 1\] \[-\frac{c}{3}|e^{-3x} _{0->\infty} = 1\] \[-\frac{c}{3}(e^{-\infty} - e^{0}) = 1\] \[c = 3\]
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ohhhh improper integrals.
do I use the same function to get the f(1/2)-(f0)?
yes
|dw:1377673616300:dw|
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