Question

c(x+2)-5=b(x-3) solve for x.
distribute first, right?
cx+2c-5+bx-3b. Am I right so far?

Answer 1

you are right but you put a (+) instead of =

cx+2c-5 = bx-3b

Answer 2

oops.
and then
cx-bx=-3b-2c+5?

Answer 3

now you need to isolate x, so keep all x's on one side as follows:

cx -bx = -3b -2c + 5 yes that is correct

Answer 4

now distribute the cx - bx as x(c-b)

Answer 5

x=-3b-2c+5/c-b?

Answer 6

CORRECT

Answer 7

yay! Thank you!

Answer 8

yw :)