Explain why (3, 5) cannot be one of the vertices of a square drawn on the coordinate plane with a vertex at the origin.

Question

akashdeepdeb · Answer

Imagine it to be like this: If 3,5 IS A POINT on the square then!
It will have 3 units to the right and 5 units at the top!
And we know that the other vertex is at the origin so we could infer from that

That The square would have a side of 3units AND a side of 5 units, which contradicts the original definition of a sqaure that states that a square has all sides equal!!! :D
Understood why a square cannot have vertices at (3,5) AND the origin? :D

anonymous · Answer

is that why they have(0,0)? ohh okay so it always has to be equal!

anonymous · Answer

thanksssss

akashdeepdeb · Answer

:)