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derivative of 2/frthrt(x^3)
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what is frthrt?
fourth root :))
\[y=\frac{ 2 }{ \sqrt[4]{x^3}}=2x^{-\frac{ 3 }{ 4 }} \] and you must know that\[y=x^p \rightarrow y'=px^{p-1}\]
\[\sqrt[b]{x^a} = x^{\frac{ a }{ b }}\]
thankyou so much @CarlosGP and @Euler271 much help thankyou!!
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you are welcome
uhmm, @CarlosGP do i have to subtract -3/4 to 1? i remember my teacher said that once you got the derivative, you have to subtract its exponent by 1..
nope, p=-3/4 and p-1=-3/4-1=-3/4-4/4=-7/4
okay okay, thank you so much big help for our exams.. having trouble with calculus :( thank you :)))))
its ok
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