Question

help with solving the equation

Answer 1

this is what I have\[2^{x}+2^{-x}=5\]
i multiply by 2^x and get
\[4^{2x}+1=5(2^{x})\]

Answer 2

try looking like this 2^x + 1/2^x = 5

Answer 3

do the quadratic formula equal to 2^x I think this part im not sure so i have
\[2^{x}=\frac{ 2\pm \sqrt{25-8} }{ 8 }\]

Answer 4

so am I on the right path or no?

Answer 5

try to use a common denominator on the left

Answer 6

well can't i just multiply both sides by 2^x and still solve the left side the same sort of way you are?

Answer 7

look at this
you have 4^x not 4^2x on the left

Answer 8

why just 4^x?

Answer 9

nvm i got it

Answer 10

it is suppose to be 2^2x not 4 because you keep the same base and add the exponents

Answer 11

2^2x = 4^x

sorry was trying to help you and do something else here at home at same time