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Given the point (3, 4) and the slope of 6, find y when x = 27 help!!
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Sorry my OpenStudy crashed :( I need to retype all of that. Grr
We can use the Point-Slope form of a line:\[\Large y-y_o=m(x-x_o)\] We were given the slope:\[\Large m=6\]And a starting point,\[\Large (x_o,y_o)=(3,4)\]And an x value,\[\Large x=27\]
We can plug all those pieces in and solve for y! :O
so y= 6x+4?
Hmm you didn't plug in the x=27. And it looks like you did something wrong in there :[ Let's see... Plugging in our values gives us,\[\Large y-y_o=m(x-x_o) \quad\color{orangered}{\to}\quad y-4=6(27-3)\]
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y= 163?
27 minus 3, \[\large y-4=6(24)\] 6 times 24,\[\large y-4=144\]Add 4 to each side,\[\large y=144+4\]
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