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How would you write the following as an algebraic expression: cos(sin^-1 12x) I know that I need to use principles of a right triangle and can do similar problems such as cos(sin^-1 (4/x) where x is the hypot. and 4 is the y value. The rest can be figured out from there but the 12x is tripping me up.
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You can write \(12x\) as \(\frac{12x}{1}\).
I had tried that but it didn't end up working. I've figured it now though!
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