Question

solve 2sinxcosx=0

Answer 1

sin2x=0
2x=sin^-1(0)

Answer 2

then what...?

Answer 3

divide both sides by 2...

Answer 4

wait

Answer 5

\(\sin x\) is 0 for angles of \(x=n\pi\), so \(\sin 2x\) is 0 for \(x=\dfrac{n\pi}{2}\).

Answer 6

would you go to
2x=sin^-1(0) +2 pi n
2x=0 + 2 pi n
x=pi n?

Answer 7

whoa whoa you are making this much harder than it is

Answer 8

^^Right you don't even need to use the identity in the first place.

Answer 9

\[2\sin(x)\cos(x)=0\iff \sin(x)\cos(x)=0\iff \sin(x)=0\text { or } \cos(x)=0\]

Answer 10

the 2 out front is a red herring, ignore it
this is rather easy right?

Answer 11

wait but u got x=pi n /2
and I got x= pi n?

Answer 12

where is cosine equal zero?

Answer 13

where is sine equal zero?

Answer 14

90 and 270 degrees
0 and 180 degrees

Answer 15

? IDK where this is taking me...