use point slope formula to find the y-intercept. the points are (1,2) and (-2,4). i found the slope, it is -2/3.
i started doing it but then when i came to 2y-4 = -4/3x - 4/3 i am stuck
can you work it out
slope formula y2 - y1 ------- x2 - x1 you have points (1,2) and (-2,4) (x1,y1) (x2,y2)
i already did that.. i got the slope.. it is -2/3.
now i need to find the y-intercept so i can write the equation of the line in standard form.
ok, I see you got the slope
no you need to find the value of b on formula y = mx + b so you have m= -2/3 use any of the 2 points for x and y and find b
I meant now
im using the point- slope formula..
so u can use that instead?
oh, ok so you are using y - y1 = m(x - x1)
no nevermind
ill use the easier way
ok , so i have 2= -2/3(1)+b
it is easier with y = mx + b
that is good so what is the value of b
did you find b yet ?
no
i was away
how do you get it, i dont understand
is -2/3 *1 -2/3 ?
yes
ok so now idk what to do
2= -2/3 +b
y = mx + b 2 = -2/3(1) + b 2 = -2/3 + b (add 2/3 to each side) 2 + 2/3 = b 6/3 + 2/3 = b can you get it now ?
ok
8/3 = b
yes
now how do i put it in standard form
points are (1,2) and (-2,4)
oh wait we dont need that info anymore
slope is -2/3 and y-int is 8/3
yes
you now have y = -2/3 x + 8/3 One good first step is "clear the fractions" by multiplying both sides (and all terms ) by 3
*update* guys, we've already found the y-intercept. now i need to write the standard form of the line.
so, 3(y= -2/3+8/3) ?
yes
but there is an x in there next to the -2/3
3y = -2x+8
now divide by 3?
Ax + By = C y = -2/3x + 8/3 (multiply by 3) 3y = -2x + 8 now add 2x to both sides and what do you get ?
standard form is Ax + By = C A is positive, and an integer. no, dividing by 3 is "going backwards" just add 2x to both sides and simplify
ok
so i add 2x to 3y and 8?
-2x i mean
like this 2x+ 3y = -2x + 8 +2x
now what
you see how the 2x's cancel each other out on the right side
on the right side you have 2 x's take away 2 x's that can be simplified to 0
now what are you left with
2x+3y = 8
you got it :)
finally :)
good job
Just for reference, you said ***when i came to 2y-4 = -4/3x - 4/3 i am stuck*** First, that should be \[y- 4= -\frac{2}{3}\left( x - (-2)\right) \\ y- 4= -\frac{2}{3}\left( x +2\right) \\ y-4 = -\frac{2}{3}x -\frac{4}{3}\] if you are trying to put that into y = mx+b form, you want the y "by itself" the first step is add +4 to both sides \[ y-4+4= - \frac{2}{3}x - \frac{4}{3} +4 \] the left side simplifies to y the right side has (unfortunately) fractions. Make 4 an improper fraction by multiplying by 3/3 you get \[y= - \frac{2}{3}x - \frac{4}{3} + \frac{12}{3} \] combine 12/3 - 4/3 to get 8/3: \[ y= - \frac{2}{3}x + \frac{8}{3} \]
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