A tricky little modulus (absolute value) equation. Any ideas please?: abs(2x+3) = 3 * abs(x) -1

Question

amistre64 · Answer

looks simple enough ...

amistre64 · Answer

where are your vertexes located?

amistre64 · Answer

if you can determone your vertexes, you can redefine the abs function into its parts and just focus on the intersection of 2 lines
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danmac0710 · Answer

Thanks for that hint.... working on it!

danmac0710 · Answer

Do you always do these ones graphically?

amistre64 · Answer

its prolly not necessary, but i work better with a visual ... 

you could just divvy it up into intervals to test the 4 line equations that make it up ...

amistre64 · Answer

from -inf to -3/2;  we play with: -(2x+3) = -3x-1

from -3/2 to 0;  we play with: (2x+3) = -3x-1

from 0 to inf;  we play with: (2x+3) = 3x-1

amistre64 · Answer

spose its only 3 setups not 4

danmac0710 · Answer

cheers man. That's helpful. Never done these type before.

phi · Answer

that is a nice visual.

if you do algebra,  you have 4 cases:   drop the abs value on both expressions
+   +
negate the left expression,   -   +
negate the right expression  +   -
and negate both  -    -

from the picture we see we will get 2 "non-solutions"
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