Question

In a right triangle named BAC, the hypotenus BA is 53 cm, AC is 28 and BC is 45.
Find out HA, HO, OB, HC, CO..

Answer 1

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Answer 2

are there any conditions for o and h

Answer 3

CO is the mediane and CH the height.

Answer 4

then o is the mid point

Answer 5

Yes.

Answer 6

then it comes in points
is it okay?

Answer 7

I have to find the other lenght with some formulas.
Should I write them ?

Answer 8

*lenghts

Answer 9

what formula's

Answer 10

h^2=b'*c'
b^2=b'*a or c^2=c'*a
a^2=b^2+c^2
h=bc/a

Answer 11

if h=bc/a
then bc=ah
then ah=28

Answer 12

are abc the lenghts of the sides or the points
write it with clarity

Answer 13

k now it is fine wait for a min i'l give you the answer

Answer 14

0b=26.5 as it is the mid point

Answer 15

28^2=oc^2+26.5^2
784=0c^2+702.25
0c^2=784-702.25
0c^2=81.75
0c=9.04

Answer 16

oh=0b/2
oh=26.5/2
oh=13.25

Answer 17

ha=oh+oa
ha=39.75

Answer 18

a^2=b^2+c^2
This formula only works with a triangle with right angles.

Answer 19

ya CHB,CHO,COB,COA are right angle triangles

Answer 20

Not COB and COA.