The lateral area of the right regular triangular prism is 18cm^2. Find the total surface area.Give answer in decimal form rounded of to 2 decimal places.
im looking for the area of the rectangle face and triangle base
This shouldn't be too hard :) Let's consider just one rectangular face... |dw:1377800484158:dw|
You with me?
yes
Now, it'd be much nicer if we knew how long this is:|dw:1377800558650:dw|
Which we do, actually... we know that the area is 18...
And the area is equal to the product of the two side-lengths...3 and an unknown number... So... three times a number is 18, what is that number?
6
That's right :)|dw:1377800697260:dw|
how come looking at the picture 3cm looks alot longer then the 6cm side.
These things are rarely drawn to scale.
?
If it bothers you that much, I'll draw a slightly more accurate figure :P|dw:1377800780026:dw|
ohhh i see
Okay, that was the easy part, though... ready for the actual 'finding the surface area'?
yes
As you can see, there are three-rectangles around the sides, each with area 18.. so that makes how many total?
??? how many what?
total area around the three rectangles...
54 cm^2
That's right, and that's the total area around the three rectangles, now find the area of one triangular base.
okay one sec
gonna try it right now
Area of an equilateral triangle given a side-length s is \[\Large A_\Delta=\frac{s^2\sqrt3}{4}\]
idk i got about 7.8
oh ill use the formula u gave me
Yes, please do :P
wait can u draw that formula on the triangle so i can see it? i dont really get it
Well, when you have an equilateral triangle, you know all sides measure the same, right? So just square the side-length and mutltiply to \(\LARGE \frac{\sqrt3}{4}\)
Howd u get|dw:1377801669518:dw|
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