Question

equation y = 2 x^2 as a polar equation

Answer 1

Use these when converting from Cartesian to Polar:\[\Large y=r \sin \theta \qquad\qquad\qquad x=r \cos \theta\]Plugging in gives us,\[\Large y=2(x)^2 \qquad\to\qquad r \sin \theta=2(r \cos \theta)^2\]

Answer 2

Do you know how to solve for \(\large r\) from that point? :D

Answer 3

yes! thanks so much!!

Answer 4

@zepdrix he knows but I don't, please show me.

Answer 5

Show us maria!! XD

Answer 6

rsin(theta)=2x^2
rsin(theta)=rcos^2(theta)
tan(theta)=2rcos(theta)
r=(sec(theta)tan(theta))/2
:)