Question

*FOR A MEDAL*
Simplify.
(4x – 3)(2x^2 – 7x + 1)
(x^2 + 4x – 3)(2x^2 + x + 6)

Answer 1

Two different problems?
Simplifying both?

Answer 2

yes

Answer 3

Okay. For the first one:
This is the equation?

\[(4x-3)(2x^2-7x+1)\]

Answer 4

yes

Answer 5

You just multiply each term:

First (4x)(2x^2-7x+1).

This equals:

8x^3-28x^2+4x

Answer 6

Do you understand what I'm doing?

Answer 7

Then (-3)(2x^2-7x+1):

-6x^2+21x-3

Answer 8

Subtract this from the first equation:

8x^3-28x^2+4x - (-6x^2+21x-3)

Answer 9

@babyblue123 Do you know how to go from there?

Answer 10

nope i don't get it

Answer 11

You're just distributing 4x-3. So you multiply it by 2x^2-7x+1.