\int { mg\cos { heta } d heta } =\int { mR\ddot { heta } } d heta

Question

\int { mg\cos { 	heta  } d	heta  } =\int { mR\ddot { 	heta  }  } d	heta

cggurumanjunath · Answer

$$\int\limits { mg\cos { \theta  } d\theta  } =\int\limits { mR\ddot { \theta  }  } d\theta $$

cggurumanjunath · Answer

integrate wrt theta ,theta dot and theta double dot. i will give medal .can any body help.

vincent-lyon.fr · Answer

Do you have a figure that goes with this equation?

cggurumanjunath · Answer

NO IT IS POLAR COORDINATE WITH CIRCULAR SURFACE,THESE ARE EQUATIONS OF MOTIONS. @Vincent-Lyon.Fr

vincent-lyon.fr · Answer

So it is a circular path.
The plane is probably vertical. Is theta defined with respect the the vertical or the horizontal?

cggurumanjunath · Answer

theta is inclined angle.

cggurumanjunath · Answer

theta is inclined angle.

cggurumanjunath · Answer

@Vincent-Lyon.Fr

cggurumanjunath · Answer

attachment

vincent-lyon.fr · Answer

This will work only if figure is as such:|dw:1377855876650:dw|
and if system is conservative.

Use ΔKE = – ΔPE

cggurumanjunath · Answer

can u explain me the steps ?

vincent-lyon.fr · Answer

Express KE wrt $\dot \theta$
Express PE wrt $\theta$

Differentiate both and equate.

cggurumanjunath · Answer

can u explain ?

vincent-lyon.fr · Answer

Well, I cannot do it for you.
Follow the steps and show your work, then we can help further.

cggurumanjunath · Answer

ke wrt theta ? what is the equation ?