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Rewrite the Cartesian equation x = -5 as a polar equation.
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\[x = r\cos(\theta)\]
Yeah! that's what I got but I need to have it in the form r(theta) and when I did that, I got r=-cos(theta)/5 and it was wrong...
\[x=-5\\r\cos(\theta)=-5\\r=-\frac{5}{\cos(x)}=-5\sec(x)\\r=-5\sec(\theta)\]
perfect, thanks!
\[x=-5\\r\cos(\theta)=-5\\r=-\frac{5}{\cos(\theta)}=-5\sec(\theta)\\r=-5\sec(\theta)\]
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sorry typos, i had x's where theta should be
np
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