How would I rewrite the conic sections by completing the square? X^2-6x+y^2+14y-62=0

Question

luigi0210 · Answer

Group terms and then move the number to the other side

luigi0210 · Answer

First of all, do you know what conic this is?

anonymous · Answer

No

anonymous · Answer

anonymous · Answer

this is good for an overview

anonymous · Answer

Okay. Thankyou

anonymous · Answer

Okay so now I have x^2-6x+y^2+14y=62

luigi0210 · Answer

Yup, so now complete the square

luigi0210 · Answer

@OffnenStudieren will help you from here

anonymous · Answer

hmm, one second

anonymous · Answer

Okay

anonymous · Answer

$$x ^{2}-6x+y^{2}+14y=62$$

anonymous · Answer

Thats what I got but I don't know how to complete the square though

anonymous · Answer

anonymous · Answer

I am good at finding resources, but I am not necessarily good at the actual math...

anonymous · Answer

Is there another resource. I am struggling with this one

anonymous · Answer

one second

anonymous · Answer