Question

A group of 11 people are going to the movies one Saturday. Adult tickets cost $11.50 each and child tickets cost $7.25 each. If the total cost for admission to the movies is $105.25, how many children attended the movie?


a. 4

b. 5

c. 6

d. 7

Answer 1

let the no of children be x
then the number of adult in grp of 11 is 11-x
as per the question we have
7.25x+11.50(11-x) =105.25
now solve for x ...

Answer 2

you cant solve this

Answer 3

u should try to solve it

Answer 4

i can help u in solving..

Answer 5

can you walk me through the steps? i just tried solving

Answer 6

first simplify the left side

Answer 7

18.75(11-x)

Answer 8

so we have
7.25x+11.50(11-x) =105.25
7.25x +126.5 -11.5x =105.25

Answer 9

7.25x -11.5x =105.25 -126.5
-4.25 x = -21.25
4.25x =21.25
x= 21.25/4.25
x=5

Answer 10

ugh thank you i still dont get some of it but illl study a little more!

Answer 11

yw
which portion u feel confused..

Answer 12

Two equations. Two unknowns. Nice combination:
Let A = Number of Adults attending
Let C = Number of Children attending

Total = A+C=11 people attending (this is one equation)
\(A\times 11.50 + C \times 7.75 = 105.25\) (our second equation)

Now, using the first we can solve for either C or A, let's go with C:

C = 11-A.

Now, stick this into the second equation. We'll then have one equation. One unknown. The best.

\(A\times 11.50 + (11-A) \times 7.75 = 105.25\)

Let's simplify. We need to bring the terms that go with \(A\) together and swing those constants to the other side of our equation:

\(\large A(11.50-7.75)=105.25-11\times7.75 \implies A={105.25-11\times7.75\over 11.50-7.75}\).

We now have A. Stick this into our first equation -- another equation with with just one unknown (after subbing). And we're done!