Question

Determine the infinite limit? (I have to present it in class. can I have explanation please).
lim + x + 2
x->-3 ------- =
x + 3

Answer 1

You might try long division.

\(\dfrac{x+2}{x+3} = 1 - \dfrac{1}{x+3}\)

The numerator is a whole lot less confusing in this form.

Answer 2

Or somewhat differently,
\[\frac{x+2}{x+3}=\frac{x+2}{x+3}\cdot\frac{\frac{1}{x}}{\frac{1}{x}}=\frac{1+\frac{2}{x}}{1+\frac{3}{x}}\]

Answer 3

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