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Mathematics 15 Online
OpenStudy (anonymous):

Real toughie of a question, anyone good at graphs?

OpenStudy (anonymous):

OpenStudy (zzr0ck3r):

thats an easy question yes im good at graphs i win

OpenStudy (anonymous):

Oh, haha, so how?

OpenStudy (campbell_st):

well if you look at the equation and table you know \[30 = kb^1 \] then \[75 = kb^2\] so rewriting the 2nd equation you can say \[75 = (kb^1) \times b\] use a little substitution to find b, then you can find k

OpenStudy (anonymous):

Hmm... I'll try~ but keep in touch k? I might not make it out haha

OpenStudy (anonymous):

Man, ya still there? I have the answers but where the hell do I get them from?

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