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d^9/d^6 = (whole number)
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what's the question?
give corresponding whole number
reduce the left hand side
are there any limitations on d?
seems like it would be 1, because there is no whole number, only exp.
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just d^9\ d^6
d^3 = whole number
d could be any whole number or cube root or whole number times cube root
so then wouldn't it just be 1, as d is understood as 1?
why is d understood to be 1?
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just comparing to a linear equation? i don't know:(
\(\Huge d = \sqrt[3]{x}, x \in \mathbb{Z}\)
\[x \in \mathbb{Z}^+\]
whole number
actually \[ x \in \mathbb{Z}^*\]
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Or \(\large\mathbb{N} \)
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