How do i find the asymptotes of y=5/(x+2)
you mean |dw:1378150481156:dw| 5/(x+2) not 5/x+2
Yes, my bad.
anyhoo to find V asymptote you have to find x+2=0 cuzz that would make the denominator so little it will cause the graph to "shoot up" vertically and therefore it is a V asymptote.
Can't it have an H asymptote also?
Now to find the H asymptote you plug in a very large number at x. typically chose 100, 1000, 100000 and you will see the graph get smaller and smaller. In fact it will reach zero and 0 is the H asymptote.
Is there a way i can find the H without plugging anything in?
y=0 is h asymptote x= -2 v asymptote
Why does y=0?
polynomial division is a simple way to find horizontal or oblique asymptotes |dw:1378150869977:dw| ignore the remainder and the quotient is the horizontal asymptote
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