Question

evaulate the difference quotient f(x)=(x+3)/(x+1), f(x)-f(1)/x-1

Answer 1

WELCOME TO OPENSTUDY!! :D

Answer 2

How much is f(1)?
If f(x) = (x+3)/(x+1)
Then f(1) = (1+3)/(1+1) = 4/2 = 2

So f(x) - f(1)/(x-1) = \(\frac{x+3}{x+1}\) - \(\frac{2}{x-1}\)

Understood? :)

Now calculate that! :D

Answer 3

isnt the x-1 should be under the whole thing

Answer 4

The question is framed in such a way that it seems like it is under f(1) only. :D

Answer 5

Then calculate

\[\frac { \frac{ x+3 }{ x+1 } - 2 }{x-1}\]

Answer 6

that is the part i am having problem with

Answer 7

forgot how to rationalize it

Answer 8

It is already rational no need to rationalize..

\[\frac{ (x+3) - 2(x+1) }{ (x+1)(x-1) }\]

Getting this?

Answer 9

yes thank you! :D

Answer 10

:)