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OpenStudy (anonymous):

(Calculus) How do i make a table of slopes of secant lines for f(x)= 2x^2 at X=2

OpenStudy (anonymous):

I assume this is what you mean correct? |dw:1378168515451:dw|

OpenStudy (anonymous):

secant line requires two points, not one if you only have one point you can find the slope of the tangent line though which, if you have not done so yet, is what you are headed towards

OpenStudy (anonymous):

oh i see, a table

OpenStudy (anonymous):

@satellite73. I think what this person means is a table showing the slope of the secant line as the second point approaches the first point and therefore showing how the secant line slowly becomes the tangent line!

OpenStudy (anonymous):

one point will be \((2,8)\) you can pick points close to 2 and make a table that way like for example \(2.1\) or \(2.01\) or \(20..1\)

OpenStudy (anonymous):

oops i meant \(2.001\)

OpenStudy (anonymous):

Haha, its basically illustrating the concept of the derivative as \[\lim_{h\rightarrow0}{\frac{f(x+h)-f(x)}{(x-h)-x}}\]

OpenStudy (goformit100):

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OpenStudy (anonymous):

Thank you

OpenStudy (anonymous):

So you are okay with the answer mustang?

OpenStudy (anonymous):

yes I am . @KeithAfasCalcLover :)

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