Question

Given: Angle ABD = 10 degrees, Angle ABC = 100 degrees, Angle EFY = 70 degrees 20', ANGLE XFY = 19 degrees 40' Prove Angle DBC is congruent to angle XFE

Answer 1

@DebbieG

Answer 2

And if you can't help it's ok :)

Answer 3

OK, I think this one just really is about adding/subtracing angle measures, some of which involve partial degrees, e.g., minutes, right?

You need to show that the measure of XFE=DBC

XFE=XFY+EFY right? So add those: 70*20'+19*40' = ?

DBC=ABC-ABD right? So subtract: 100* - 10* =?

That should about do it. :)

Answer 4

Yes
So 70*20' + 19*40' = 90*
100*-10*=90

Is that right?

Answer 5

Yeppers! :)

Answer 6

Because there are 60min in 1deg.... so the

70*20'+19*40' = (70+19)* + (20+40)'=89*+60'=89*+1*=90*

Answer 7

Ok! Thank you soo much :) You're a big help

Answer 8

You're welcome, happy to help! :)

Answer 9

Do you think it's ok if once in a while I tag you in some problems? I think you're really good at helping and explaining problems

Answer 10

Aww, thank you! Sure, feel free! Just know that sometimes I am logged in but nowhere near my computer, lol. :)