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2^x=11
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switch it to a log \[\log_{2}11=x\]
\[b^x=A\iff x=\frac{\ln(A)}{\ln(b)}\] if you want a decimal approximation for this
would it be 3.31 ?
i.e. if you want to compute a number, compute \[x=\frac{\ln(11)}{\ln(2)}\]
seems reasonable since \(2^3=8\) we can check
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no i get something different http://www.wolframalpha.com/input/?i=log%2811%29%2Flog%282%29
ln and log are the same, right?
You were right satellite73
ln is natural log with base e Log is base 10
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