what is tan of 2pi/3 also what is the csc of pi/4 (sorry still a bit confused)
Do you have a unit circle handy on you to help ya out with this?
yes im looking at it. but I lost the one that has all my notes :(
Ah x_x Well, let's start out with knowing that tangent is the same and sin divided by cosine. SO if we want tangent of 2pi/3, we take the sin of 2pi/3 and divide it by the cos 2pi/3. If you can look up those values then we can find out what that is : )
\[\frac{ \sin(\frac{ 2\pi }{ 3 }) }{ \cos (\frac{ 2\pi }{ 3 }) }\]
sin of 2pi/3 is \[\sqrt{3}\div2\] and the cos is -1/2
Correct. so now divide those 2: \[\frac{ \frac{ \sqrt{3} }{ 2 } }{ \frac{ -1 }{ 2 } } \]
Or simply: \[\frac{ \sqrt{3} }{ 2 }*-2 \]
so would it be -sqrt of 6?
Nope. Just cancel out the two on top and bottom in what I have posted above.
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