Line A is perpendicular to the line with equation y = -1/3 x and the point is on line A . Which of the following is the equation of line A
Can you tell me the slope of this line y=(-1/3)x? hint: y=mx+c is the general equation of straight line with slope m and y-intercept c
When we we are given an equation of a line and asked to find a line perpendicular to it what we should do is to take the slope in your case is -1/3x and get its negative reciprocal which is -(1/m) since your m=-1/3 its negative reciprocal is m=3 that negative reciprocal which is 3 is now you slope for the line you are trying to find the equation of line A is then y=3x+b b being the y intercept of that line
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