Graph this f(x)=√x+2-3. I actually have an answer but don't know if it is correct.
|dw:1378232185885:dw| mine was similar to this but more accurate on a graph
not exactly... do you understand the shifts and such?
Yes
What I don't understand is how to change the equation to see the shifts (a, h, k)
set whatever is inside the sqrt = 0 and solve. that will get you h. the k is whatever is outside is the k
so I should solve √x+2
set x+2 = 0 and solve for x. that will be your h.
how am I supposed to solve if it is 0 I don't understand.
subtract 2 from both sides to solve for x
so f(x)=0-5?
I mean f(x)= √0-5
\[f(x) = \sqrt{x+2} - 3 \text{, yes or no?}\]
yes
so inside the square root, what value of x makes the inside = 0?
-2
great! that is h. in terms of x, is -2 to the left or right of the origin?
left?
correctamundo! now, that negative 3 is a shift in the y direction. is that going to be up or down?
down I believe
that's right! so your graph will pellet 2 to the left and down 3.
shift not pellet
How about the stretch and and reflection? (b and a)?
there isn't any of those in this problem. if f(x) is the parent, then g(x) = af(x-h) + k is a horizontal shift of h, a vertical shift of k and a stretch of a if |a|>1 or a compression if |a| <1. if a< 0, then it is a reflection.
see that is not what my teacher taught us, she said we have to factor the x+2 out of the equation to give us all of them but thanks.
i'm not sure what your teacher is going for but i'm really not seeing the connection here. good luck
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