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Solve for y... (1/(y^2)+3)=(x^3)+2x-5 someone please help
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So how far do you get on this problem?
I feel like the first step should be factoring the right side but I don't know
So you can't factor the right side. There is no reason to since you are solving for y. So your go is to get Y by itself. So do any algebra you can to get Y alone on either side of the equation.
y=1/\[y=1/\sqrt{x ^{3}+2x-5}\]
?
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i meant -8
That seems right. But you can not forget the Plus or Minues 1 since you Square rooted the 1! Remember you get two values, a positive and negative, when square rooting a number.
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You are welcome!
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