Question

Could someone walk me through this problem?

Answer 1

\[1. (2x^3 + x - 10) - (5x^2 - 7x) + (3x^3 - 2x^2 - 9x + 3)\]

Answer 2

first you need to distribute.

Answer 3

\[2x ^{3}+x-10-5x ^{2}+7x+3x ^{3}-2x ^{2}-9x+3\]
You add the like terms together

Answer 4

Does that kind of help?

Answer 5

Okay, so:

\[2x^3(-5x^2 + 7x)\]
-10x^5 + 14x^4

\[x(-5x^2 + 7x)\]
5x^3 - 7x^2

\[-10(-5x^2 + 7x)\]
50x^2 - 70x

-10x^5 + 14x^4 + 5x^3 - 7x^2 + 50x^2 - 70x, then combine like terms.

Answer 6

-10x^5 + 14x^4 + 5x^3 + 43^2 - 70x? + (3x^3 - 2x^2 - 9x + 3)

Answer 7

Do I have to distribute again or just combine like terms?

Answer 8

yes \(\bf (2x^3 + x - 10) - (5x^2 - 7x) + (3x^3 - 2x^2 - 9x + 3)\\ \quad \\
2x^3 + x - 10 - 5x^2 + 7x + 3x^3 - 2x^2 - 9x + 3\\ \quad \\
(2x^3+ 3x^3) (+ x+ 7x- 9x) (- 5x^2 - 2x^2) (- 10+ 3)\)

Answer 9

The way @jdoe0001 did it is correct

Answer 10

Oh, okay. So, is the answer then 6x^6 + 17x - 3x^2 - 7?

Answer 11

\(\bf -5 -2 \ne -3\)

Answer 12

Oops, 6x^6 + 17x - 7x^2 - 7

Answer 13

well... \(\bf 1 + 7 -9 \ne 17\)

Answer 14

I messed the whole thing up, I guess? 6x^6 - 1x - 7x^2 - 7

Answer 15

Are you supposed to add or multiply the first part of the problem? (2x^3 + 3x^3).

Answer 16

notice that \(\bf (2x^3+ 3x^3)\) is not multiplying, is ADDING

Answer 17

they just happen to be grouped in paretheses

Answer 18

There is multiplication when you distribute but after that everything else is either adding or subtracting

Answer 19

Alright, thank you both!

Answer 20

No Problem

Answer 21

yw