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Mathematics 20 Online
OpenStudy (anonymous):

A = B√C

OpenStudy (anonymous):

are you asking a question

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

so what is it

OpenStudy (anonymous):

A = B√C solve for b

OpenStudy (anonymous):

oh hold on one sec

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

B=(A√C)/C

OpenStudy (anonymous):

wow ur smart!! how dod u get that?

thomaster (thomaster):

yea... how did you get that. You know you're not supposed to give out answers here?

OpenStudy (anonymous):

isolate the variable by using inverse operations

OpenStudy (anonymous):

tho monster what the freak dude!! wow ok thanks pal!!!

OpenStudy (anonymous):

wait that amswer isnt right?

thomaster (thomaster):

No it's not right. To isolate B, you'd have to divide both sides by √C. So it would be \(\large B=\Large\dfrac{a}{\sqrt{c}}\)

OpenStudy (anonymous):

ok ywa that makes more sense thanks!

OpenStudy (anonymous):

thats not it wither my friends

OpenStudy (anonymous):

either

thomaster (thomaster):

That's the answer To check it: http://www.wolframalpha.com/input/?i=A+%3D+B%E2%88%9AC++solve+for+B

OpenStudy (anonymous):

A = BC2 solve for b..??? i dont get these

OpenStudy (anonymous):

now that is confusing

OpenStudy (anonymous):

i know!!!:/

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