Question

27^{5 x} = 9^{x+3}.
Find X

Answer 1

\(27^{5x} = 9^{x+3}\)
It seems like you should make the bases the same, then set the exponents equal to each other and solve for x.

Answer 2

any idea how i could make the bases the same. i tried but failed to do so.

Answer 3

\(3^3=27\) and \(3^2=9\)

Answer 4

Thanks alot

Answer 5

You're Welcome.
One last thought...
\((3^3)^{5x}=3^{15x}\)
When raising a power to a power, you multiply.

Answer 6

Got it. Thank you again for your help