Simplify |x| - |-x|.

0
2^x
x^2
-x2

Question

Simplify |x| - |-x|.


0
2^x
x^2
-x2

anonymous · Answer

|x| =|-x| by its definition. so same number - same number?

anonymous · Answer

Ex. 

|1| - |-1|

1 - 1 = 0

ttop0816 · Answer

so it would be 0?

anonymous · Answer

|x| returns magnitude ignoring the sign... |x| and |-x| are parallel going different direction in 2D. soooo they have equal magnitude. That is why as i said earlier |x|=|-x|

ttop0816 · Answer

-x^2?...

anonymous · Answer

nope

anonymous · Answer

the | | mean absolute value. 

so |-3| would be 3 

ex. 

|87| = 87 

|-979| = 979 

so: 

|x| - |-x|

can you give it a try?

anonymous · Answer

Remember that $|x| = |-x|$.

anonymous · Answer

If you subtract $|-x|$ from both sides of this equation you get: $$
|x|-|-x| = 0
$$

ttop0816 · Answer

oh then it would just be x^2!

anonymous · Answer

nope

ttop0816 · Answer

2x?

anonymous · Answer

nope. 

take a look at what @wio and @katherine.ok and @some_someone wrote :)

tkhunny · Answer

For x > 0, |x| = x and |-x| = x For x < 0 |x| = -x and |-x| = -x For x > 0, |x|=|−x| ==> x = x For x < 0, |x|=|−x| ==> -x = -x ==> x = x Can you think of ANY number that is not equal to itself?