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Find f(x-1) when f(x) = 4x^2 – 3x + 3 ???
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... 4(x-1)^2 - 3(x-1) + 3 expand it
sub in (x-1) in all of the x's in your equation.
Like @nphuongsun93 did.
ok then what
When you spuare a term you are multipliying it by itself. Write it out like this 4(x-1)(x-1) - 3(x-1) + 3. The first step is to expand ^ the (x-1)(x-1).
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Did you do it?
4x^2 – 11x + 4
is it right
4(x^2 - 2x + 1) try expanding again.
4x^2 + 9x + 4
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:/ right
mm the answer you gave me is not the chooses i have
its zero
what r ur choices?
4x^2 – 11x + 10 4x^2 + 9x + 4 4x^2 – 11x + 4 -11x^2 + 4x + 10
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its the first one
u sure?;)
im possitive ;)
ok thanks
anytime :)
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