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Solve the following pair of equations for x and y : 3x+2y=9xy ; 9x+4y=21xy ; x, y ≠ 0.
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do you know the method of elimination ?
multiply 1st equation by 3 and subtract it from 2nd equation, what do u get ?
yup elimination method...
10y = 48 xy?
did you add, instead of subtracting ? :P
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subtract
cut the 9's
9x+6y=27xy subtract from 9x+4y=21xy so, whats 6y-4y =... ?
i thnk we shud multiply by -3 and add
2y
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multiply by +3 and subtract is exactly equivalent to multiply by -3 and add do what you are comfortable with :)
you should get 2y=6xy in the end, ask me if you don't get that
yup...............finally gt it..................thnx man!!
welcome ^_^
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