Ask your own question, for FREE!
Algebra 15 Online
OpenStudy (anonymous):

Let g(x) be the indicated transformation of f(x). Write the rule for g(x). Horizontal Compression by a factor of 0.5. what i know : graph shows : y=3.5/1x+0 equation for horizontal compression : f(1/bx) = g(x)

undeadknight26 (undeadknight26):

Yea don't worry about that guy

undeadknight26 (undeadknight26):

ill try to help u but im only a 9th grader...please hold on

OpenStudy (anonymous):

ok

undeadknight26 (undeadknight26):

Sorry i don't think i no this formula yet.

OpenStudy (anonymous):

I just need help on this I do not care for your stupid comments

OpenStudy (jdoe0001):

y = A( Bx + C ) + D A = compresses/squeezes or expands the graph

OpenStudy (anonymous):

I am done since I can't even get help without someone being a bully.

undeadknight26 (undeadknight26):

don't u dare hit that enter button swole

undeadknight26 (undeadknight26):

jdoe can u help me with my problem?

OpenStudy (jdoe0001):

hmm what is it?

undeadknight26 (undeadknight26):

http://openstudy.com/study#/updates/52278636e4b0750826e333db

OpenStudy (jdoe0001):

@undeadknight26 btw, put your mouse over "nick" and click on "block user" FYI

undeadknight26 (undeadknight26):

who is "nick"

OpenStudy (jdoe0001):

nick as in Swole15Nation anyhow, he dashed for now

undeadknight26 (undeadknight26):

i don't think he can kick my butt...i no ninjitsu and mma...

OpenStudy (jdoe0001):

hehhe anyhow

OpenStudy (goformit100):

"Welcome to OpenStudy. I can guide regarding this useful site; ask your doubts from me, for it you can message me. Please use the chat for off topic questions. And remember to give the helper a medal, by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/code-of-conduct ). Please take a moment to read it."

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!