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To get rid of the square root. you'd have to raise both sides to the power of two. That's the first step.
So I guess you can figure out the answer now :)
B?
\(\large\sqrt{6x+4}=8\) \(\large(\sqrt{6x+4})^2=8^2\) \(\large 6x+4=64\) You know how to solve it now?
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Dident you square root both sides??
Yea, raising both sides to the power of two = squaring both sides
when you square a square root, the square root will go away, leaving the part under the root. \(\Large(\sqrt{x})^2=x\)
Same for taking the square root of something that's squared. \(\Large\sqrt{x^2}=x\) Square root and the square are opposites (inverse functions)
So was I right.
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