I need help with graphs and functions..algebra 2
And also, determine if y is a function to x. x^2 = 3y + y
@amistre64
@ganeshie8
which q you stuck wid ? :)
29 and 30! And sorry is the picture up side down?
its okay :) look at the curve in pic 29, it is starting at 0, and going up forever.. so its range is : x >= 0
wat do you knw about its domain ?
it's infinite?
kindof yes :) for domain, you look left and right of curve, its goin forever in both directions. so domain is : all real numbers
basically we don this :- for range, look \(\text{up and down}\) of the curve for domain, look \(\text{look left and right}\) of the curve
can you do the same for pic 30, and tell me whats the range is ?
All I know is that 30 is not a function
thats right ! its not a function !!
for finding range, look up and down of that curve
so it doesnt have a domain or function?
or range* not function lol
down, it is -1, up it is +1 so the range is all numbers between -1 and 1 we represent it as : [-1, +1]
domain and range will be there for every relation
and is domain infinite again?
wat about domain for this ? :) look left and right, and see if u can figure this out...
noo.. look at the pic., this time, the curve is not going left and right forever
-3 and 3 ?
left, it stopped at -3 right, it stopped at +3 so the domain is all numbers between -3 and +3 we represent it as [-3, 3]
Excellent ! yes everything between -3 and 3
Ohh!:) thank you so much! and i need help with one more thing!
sure :)
determine if y is a function to x. x^2 = 3y + y
x^2 = 3y + y ? is the right side, really, 3y+y ?
yes
ok, solve y x^2 = 3y + y x^2 = 4y x^2.4 = y y = x^2/4
now graph this relation, and see vertical line test passes
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