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Mathematics 7 Online
OpenStudy (anonymous):

I need help with graphs and functions..algebra 2

OpenStudy (anonymous):

OpenStudy (anonymous):

And also, determine if y is a function to x. x^2 = 3y + y

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

which q you stuck wid ? :)

OpenStudy (anonymous):

29 and 30! And sorry is the picture up side down?

ganeshie8 (ganeshie8):

its okay :) look at the curve in pic 29, it is starting at 0, and going up forever.. so its range is : x >= 0

ganeshie8 (ganeshie8):

wat do you knw about its domain ?

OpenStudy (anonymous):

it's infinite?

ganeshie8 (ganeshie8):

kindof yes :) for domain, you look left and right of curve, its goin forever in both directions. so domain is : all real numbers

ganeshie8 (ganeshie8):

basically we don this :- for range, look \(\text{up and down}\) of the curve for domain, look \(\text{look left and right}\) of the curve

ganeshie8 (ganeshie8):

can you do the same for pic 30, and tell me whats the range is ?

OpenStudy (anonymous):

All I know is that 30 is not a function

ganeshie8 (ganeshie8):

thats right ! its not a function !!

ganeshie8 (ganeshie8):

for finding range, look up and down of that curve

OpenStudy (anonymous):

so it doesnt have a domain or function?

OpenStudy (anonymous):

or range* not function lol

ganeshie8 (ganeshie8):

down, it is -1, up it is +1 so the range is all numbers between -1 and 1 we represent it as : [-1, +1]

ganeshie8 (ganeshie8):

domain and range will be there for every relation

OpenStudy (anonymous):

and is domain infinite again?

ganeshie8 (ganeshie8):

wat about domain for this ? :) look left and right, and see if u can figure this out...

ganeshie8 (ganeshie8):

noo.. look at the pic., this time, the curve is not going left and right forever

OpenStudy (anonymous):

-3 and 3 ?

ganeshie8 (ganeshie8):

left, it stopped at -3 right, it stopped at +3 so the domain is all numbers between -3 and +3 we represent it as [-3, 3]

ganeshie8 (ganeshie8):

Excellent ! yes everything between -3 and 3

OpenStudy (anonymous):

Ohh!:) thank you so much! and i need help with one more thing!

ganeshie8 (ganeshie8):

sure :)

OpenStudy (anonymous):

determine if y is a function to x. x^2 = 3y + y

ganeshie8 (ganeshie8):

x^2 = 3y + y ? is the right side, really, 3y+y ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

ok, solve y x^2 = 3y + y x^2 = 4y x^2.4 = y y = x^2/4

ganeshie8 (ganeshie8):

now graph this relation, and see vertical line test passes

ganeshie8 (ganeshie8):

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