Question

plzz help me ASAP..!

Answer 1

Start by factoring each of the numbers under the root-sign.

Answer 2

cn u shw hw??

Answer 3

@dape ???

Answer 4

start by factoring first 45, 50, 147 under their root

Answer 5

am learnin dis fo first tym..cn u shw hw..??@petiteme

Answer 6

what are the factors of 45?

Answer 7

uhm..5,9,1,45

Answer 8

so 9*5 right? then its like this \[8\sqrt{9*5}\]

Answer 9

do it also to \[2\sqrt{50} - 3\sqrt{147}\]

Answer 10

nope. find the factors wherein you can use the square root. so this is the right one \[2\sqrt{25*2}\]

Answer 11

its \[3\sqrt{49*3}\]

Answer 12

So we got \[8\sqrt{9*5} + 2\sqrt{2*25} - 3\sqrt{49*3}\]

Answer 13

ohk..den

Answer 14

perform the square root :)
First,
\[2\sqrt{9*5}\]\[8*3 \sqrt{5}\] because the square root of 9 is 3. We put 3 already outside the square root :)

Answer 15

Second,
\[2\sqrt{2*25} \] the square root of 25 is 5 so
\[2*5 \sqrt{2}\] we put the 5 outside the square root

Answer 16

Third,
\[3\sqrt{49*3}\] the square root of 49 is 7
so
\[3*7\sqrt{3}\]
we put 7 outside the square root

Answer 17

So its \[8*3\sqrt{5} +2*5\sqrt{2} - 3*7\sqrt{3}\]
Do the math
\[24\sqrt{5} + 10\sqrt{2} - 21\sqrt{3}\]

Answer 18

@juhaINA do you get it? :)

Answer 19

yup

Answer 20

thnx soo muJ

Answer 21

you're welcome :) anytime :)