a gas tank on a dock has a small puncture and is leaking gas at a rate of 1cm^3/min into a lake. it forms circular slick that is 1mm thick on the surface of the water.
a)find the amount of gas leaked as a function of time
b) what is the radius of the slick a a function of volume
c) what is the raduis of the slick as a funtuion of time

Question

a gas tank on a dock has a small puncture and is leaking gas at a rate of 1cm^3/min into a lake. it forms circular slick that is 1mm thick  on the surface of the water.
a)find the amount of gas leaked as a function of time 
b) what is the radius of the slick a a function of volume 
c) what is the raduis of the slick as a funtuion of time

anonymous · Answer

Im on question b

anonymous · Answer

im getting r=sqrt(v^2/pi(0.1))

anonymous · Answer

$$r=\sqrt{v^2/\pi(0.1)}$$

anonymous · Answer

sorry v is not squared

anonymous · Answer

but online answers show it as being pi(0.1)h
which is weird cuz 0.1 is h
am i wrong?

anonymous · Answer

any help appreciated guys

anonymous · Answer

no v is not squared and yes .1 would be the height in cm

anonymous · Answer

cuz this one website the guy solves it to be sqrt(v/pi(0.1)h)

anonymous · Answer

so i was wondering if im missing something

anonymous · Answer

http://www.algebra.com/algebra/homework/Functions/Functions.faq.question.202485.html

anonymous · Answer

this is where the guy keeps using h and its a pretty legitimate website

anonymous · Answer

when he writes pi(.1)h he is just showing that the .1 belongs to the height

anonymous · Answer

do you have to plug the values in or just solve. r=sqrt.(v/pih)