Question

How do I graph a tangent line at a point

Answer 1

find the slope of that point by taking the derivative

Answer 2

Can I have a pic of tangent of 6 at point (3,9)

Answer 3

I need it badly...I would really appreciate it

Answer 4

what is the function of the line

Answer 5

Y=X^2

Answer 6

okay ill walk you through it

Answer 7

Thanks

Answer 8

to find the slope at any point we first take the derivative:
d/dx(Y) = d/dx(X^2) = 2X
good so far?

Answer 9

I don't get that...

Answer 10

have you learned derivatives yet

Answer 11

A while ago

Answer 12

Can. Have a pic of the function and tangent line

Answer 13

A site that u can graph it on is desmos.com

Answer 14

ok, well its just the power rule the derivative of x^a where a is some power is a*x^(a-1)
so here a = 2
so its 2*x^(2-1) = 2x
and im going to show you how to do it not draw it for you :)

Answer 15

Ya ok...but I need to know where the y intercept of the tangent line is

Answer 16

thasts fine we will get to that

Answer 17

Ok thanks

Answer 18

Can u figure it out and tell me

Answer 19

so like we said the slope at any point is 2*x.
So to find the slope of the tangent linet at (3,9) we plug in the x coordinate 3 into 2*x and obviously get 6.
Good?

Answer 20

I will figure the steps out on my own

Answer 21

Is that ok?

Answer 22

so now the slope is 6:
use y = mx + b form to find the answer.
since the line hits (3,9) you can use x = 3, y = 9 and solve for b.
then you should be able to graph a line

Answer 23

Bt y=x^2 is a quadratic

Answer 24

Not linear

Answer 25

yes but the tangent line is linear

Answer 26

Ok...I am bit in a rush so can u tell me the answer and I will figure it out later

Answer 27

This is exactly how to find the line you are supposed to draw, just do it
"so now the slope is 6:
use y = mx + b form to find the answer.
since the line hits (3,9) you can use x = 3, y = 9 and solve for b.
then you should be able to graph a line"

Answer 28

Thanks!

Answer 29

your welcome. hope it helped :)