Question

Anyone with a scientific or graphing calculator plz help!

I don't have the appropriate calculator, could someone find log(-.39) and ln(-.39) ?? you have to press the inverse button

Answer 1

Uh, log and ln of anything negative is undefined.

Answer 2

that's why you have to use inverse

Answer 3

What is there to inverse? O.o If you only give me an expression of ln(-.39), I dont see what can be done.

Answer 4

well its actually .39=logx and .39=lnx my bad but I still don't have a calc

Answer 5

Now thats infinitely different, lol.

Answer 6

yup Im out of it sorry

Answer 7

Well, do you know what youd normally have to do if you had a calculator?I have no problem doing the calculator work, just need to make sure you would know whats going on.

Answer 8

well would it be 10 to the power of the number? in this case .39? im looking at some notes and it shows logx=5 and they go on to do 10^5 and get the big ol number

Answer 9

Yeah. Because when logx is written with no base, the base is assumed to be 10. So you would have 10^.39 = x, right. And for the ln portion?

Answer 10

idk bout that one I don't get what the notes are saying....

Answer 11

wait I think I got it

Answer 12

Well, if its ln, you "e" both sides.

Answer 13

So for log(x) = .39, we change it into
10^.39 = x

for ln(x) = .39, we e both sides and have
x = e^.39

Answer 14

i used an online calc and got the answers :)

Answer 15

Alright xD But yeah, knowing what is actually going on is still important.

Answer 16

yeah, I got it a lil bit before you responded again but th website is lagging on my comp for some reason... thanks though!

Answer 17

Yeah, np :3

Answer 18

inverse of lnx is e^x