What is the slope of the line that is perpendicular to y = 2x – 3?
can you find slope of this line ? y= 2x-3 ?
the slope is 0 for y=2x-3
nopes, how ? compare it with, y= mx+c where m= slope
oh, so then the slope is 2?
yes now product of slope of perpendicular lines =-1 so, to get the slope of perpendicular line, you just take negative reciprocal of this slope
so then the slope of the perpendicular line would be -2?
\[ 0=\begin{bmatrix} 1 \\ m \end{bmatrix} \cdot \begin{bmatrix} 1 \\ m' \end{bmatrix} \implies 1 + mm' = 0 \implies mm' = -1 \implies m' = -\frac 1 m \]
you forgot to do reciprocal ?
yeah, It's been a while since I've done this
So if \(m\) is the slope of a line, a line who is perpendicular has slope \(m' = -\frac 1 m\).
what is the reciprocal of 2 ?
ok, so then the reciprocal of 2 would be \[- \frac{ 1 }{ 2 }\] right?
reciprocal of 2 is 1/2 so, the slope of line will be -1/2 yes, correct.
slope of perpendicular line**
Okay, thanks!
welcome ^_^
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