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So when evaluating int 12cos^2(8x)dx I ended up with zero and that's not supposed to happen...can someone give me a hand?
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is this your question : |dw:1378485438274:dw|
yes
ok, first you can use the identity of trigono : cos^2 (a) = (1 + cos(2a))/2
so, cos^2 (8x) = (1 + cos(2(8x)))/2 = (1 + cos(16x))/2, agree ?
yeah I follow so far
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