Question

is f(x)=xabs(x^2) an odd, even or neither function

Answer 1

even i belive

Answer 2

you just look at the expontes

Answer 3

it is online hw and i only have one attempt to get it right

Answer 4

u have to be 100% sure

Answer 5

\[f(x)=x \left| x^2 \right|\]

Answer 6

is it odd, even or neither

Answer 7

So in theory, IF:
\(f(x)=f(-x)\) THEN It is even.
\(-f(x)=f(-x)\) THEN it is odd.

Answer 8

So if we know that \(f(x)=x|x^2|\), Lets check to see if the identities are correct!
Try computing f(-x) and -f(x) and see what those return and if it fits any of the above equations.

Answer 9

can u give me an answer?

Answer 10

please

Answer 11

i get confused with the absolute value

Answer 12

I don't get what hes saying what my teacher told me is you just look at the exponets

Answer 13

Oh yeah...good point. Try this:
\[f(x)=x|x^2|\]
\[f(-x)=(-x)|(-x)^2|=-x|x^2|\]
\[-f(x)=-(x)|x^2|=-x|x^2|\]
So since \(f(-x)=-f(x)\) The function is odd.

Answer 14

I am \(200\%\) sure that \(f(x)=x|x^2|\) is odd

Answer 15

thanks

Answer 16

what do i do if it gives me two graphs

Answer 17

If what does...?

Answer 18

the hw

Answer 19

it gives me http://roy.math.umn.edu/webwork2_course_files/umtymp-calculus1-f13/tmp/gif/muzzammil-Q-raza-524-setReview_and_Rate_of_Changeprob4image1.png

Answer 20

don't know if the link works

Answer 21

@KeithAfasCalcLover

Answer 22

good luck t(-_-)t

Answer 23

i wil do it on my own i just want u to help me start

Answer 24

And what you want to do with the graph?

Answer 25

find out if they r odd, even or neither

Answer 26

@KeithAfasCalcLover

Answer 27

Visually you can identify a function as odd even or neither by imagining this:
If the right or left side of \(f(x)\) can be rotated about the y-axis to match the other side, it is even.
If the If the right or left side of \(f(x)\) can be rotated about the line of \(y=x\) or \(y=-x\) to match the other side, it is odd.
Otherwise it is neither.

Answer 28

so what do u think

Answer 29

lol why don't you think instead of just asking for answers

Answer 30

i think its red=even and blue=odd. what do u think

Answer 31

Well think about it, could you flip one side of the red over the y axis to match the other?

Answer 32

have u looked at the graph

Answer 33

Yes muzzamil, I have.

Answer 34

buddy i really need help on this

Answer 35

LOL KEITH WALK AWAY NOW

Answer 36

Have you?
Take a look. Imagine you grab one side and fold it over the y-axis. Does it fit on the other side?

Answer 37

i said i think red is even and blue is odd. atlesat i am trying

Answer 38

i asked if u thouht i was right

Answer 39

Well why do you think that?

Answer 40

and he is asking you a question and you haven't answered it and if you did it answers your question llol

Answer 41

kramer instead of wasting ur precious time maybe u should leave. i did what u told me to

Answer 42

trust me my time at the moment is not precious

Answer 43

i keep asking ur opinion cuz my a$$ is on the line. my parents get pissed if i mess up on my hw. its an asian thing

Answer 44

didn't you get taught the lesson in school?

Answer 45

i also want to watch football this weekend and i need this done. i am a ninth grader taking calculus at the university of minnesota. the professors suck there

Answer 46

bro that isn't calculus that's pre calc

Answer 47

its th first chapter of the book

Answer 48

u dont do derivatives the first day

Answer 49

x is odd.

x^2 is even

abs(x^2) is redundant because x^2 is always positive.

Therefore, f(x) = x^3 and it is definitely odd.

Answer 50

we already solved that. we r on the graph one. i posted a link @tkhunny

Answer 51

I would have to agree that it is not calculus but it may be review of pre calc in the beginning.

How youre accepted in Minnesota University at grade 9 is beyond me.

Answer 52

because hes a liar lol

Answer 53

UMTYMP. university of minnesota talented youth math program

Answer 54

look it up. mathcep.umn.edu

Answer 55

@llkramer mathcep.umn.edu

Answer 56

I saw the solution. I just wanted to make sure we used the word "redundant".

Answer 57

@tkhunny this guy just wants answers no work don't waste your time

Answer 58

@llkramer did u look it up?

Answer 59

\[f(x)=x|x|^2\]
\[f(2)=2\times |2|^2=\]
\[f(-2)=-2\times |-2|^2=-8\]

Answer 60

we already solved this @satellite73 . we r now on the link i posted with the two graphs

Answer 61

http://roy.math.umn.edu/webwork2_course_files/umtymp-calculus1-f13/tmp/gif/muzzammil-Q-raza-524-setReview_and_Rate_of_Changeprob4image1.png

Answer 62

DONT GIVE HIM A ANSWER BRO

Answer 63

what a pretty picture
what are you supposed to do with it?

Answer 64

AN**

Answer 65

r the graphs even, odd, or neither

Answer 66

@satellite73

Answer 67

i think red=even and blue=odd

Answer 68

the one that is symmetric with respect to the \(y\) axis is even
the one that is symmetric with respect to the origin \((0,0)\) is odd

Answer 69

yes, you are right

Answer 70

LOL @satellite73 "What a pretty picture" haha that got a good laugh a
out of me.

Answer 71

THANK YOU @satellite73 FINALLY SOMEBODY WHO COULD ACTUALLY TELL ME IF I WAS RIGHT OR WRONG.

Answer 72

@satellite73 That's EXACTLY what I thought when It was first shown to me

Answer 73

THEN Y COULDN''T U SAY THAT

Answer 74

U COULD HAVE SAVED US LIKE 30 MIN

Answer 75

Though math is about right and wrong, It is even more about the WHY. "yes" and "no" wont get you very far without the WHY.

Answer 76

WELL THANKS FOR THE FIRST ONE ANYWAY

Answer 77

Is this some sort of an "ALL CAPS RAGE" or so?

Answer 78

idk. bye

Answer 79

Bye. GOOD LUCK