John has 51 coins. Dimes and quarters worth $9.60. How many of each coin does John have?

Question

anonymous · Answer

divide .25 (quatrer) into $9.60
dose that get yo started??

anonymous · Answer

x are dimes and y are quarters when you add all values you get

10x+ 25y= 9.60

when you add your quarters and dimes you get 51 coins
x+y=51

anonymous · Answer

You now have a system of equations. You can either use substitution or addition of subtraction of the equations.

anonymous · Answer

use substitution method

taylormarie213 · Answer

ah i'm braindead. Can you show me how to set up the substitution or addition of subtraction equations? please?

anonymous · Answer

i'm sorry i have to go ill try to help you later if ur answer didn't get answered but i think someone else might help you sorry

anonymous · Answer

x+y=51 isolate for x

x=51-y
Now replace everything on that x with 51-y
10x+ 25y= 9.60

turns into

10(51-y)+25y=9.60

Solve for y now. 

Once you find y use that value and plug it back in into any equation then solver for x

taylormarie213 · Answer

|dw:1378594124367:dw|

anonymous · Answer

sorry its suppose to be .10*(51-y)+.25*y=9.60 
you should get y=30

taylormarie213 · Answer

thank you my friend helped me :]