Question

Calc 1 Limit Problem
No L'hopital's rule allowed!

Posting limit

Answer 1

\[\lim_{x \rightarrow 1}\frac{ \sqrt{1+3x}-2 }{ \sqrt{x+8}-3 }\]

Answer 2

Multiplying by the conjugates didn't quite work out, did it?

Answer 3

Nope. Neither top nor bottom.

Answer 4

@nincompoop will help,
reeezun: cuz b0red.kthxbye.

Answer 5

\(\color{blue}{\text{Originally Posted by}}\) @SithsAndGiggles
Worked for me:
\[\frac{\sqrt{3x+1}-2}{\sqrt{x+8}-3}\cdot\frac{\sqrt{3x+1}+2}{\sqrt{3x+1}+2}\cdot\frac{\sqrt{x+8}+3}{\sqrt{x+8}+3}\]
yields
\[\frac{3x+1-4}{x-1}\cdot\frac{\sqrt{x+8}+3}{\sqrt{3x+1}+2}\]
\(\color{blue}{\text{End of Quote}}\)

Answer 6

Ah, both conjugates, not just one. Duh x_x

Answer 7

Yup, works out nicely after that.

Answer 8

Alrighty, cool, thanks :3

Answer 9

Welcome