@surjithayer @Luigi0210
Isn't that the same question?
oooo sorry hold on
i think its (x+4)1 idk if im correct
Did you switch y and x?
its suppose to be y
This is how you start: \[x=\frac{y}{4}-1\] Solve for y
*+1 Sorry
@divagirl421 , To be fair, I have not worked very much with these types of problems. I believe your correct in accordance with my Algebraic background. But, be sure to check your work to insure your correct. God Bless, and have a wonderful night! \(\color{red}{Chance}\) ___________________________________________ @Luigi0210 I learned to do Latex.
1/4y+1?
@Luigi0210
Switch y and x from the original \[x=\frac{y}{4}+1\] Subtract 1 \[x-1=\frac{y}{4}\] Multiply by 4 \[4x-4=f^{-1}(x)\]
Is it asking for the inverse of x or y? Psymon.
y. Interesting, looks like a trick question.
Exactly
You need to rearrange the function to make it a function of y first. y = (x/4) + 1 So to make f(y), we solve for x first. x = 4(y-1) = f(y) Now find the inverse of that.
so i just switch then solve
i believe its x
Nah, it says to find the inverse of f when it is a function of y. Which means you have to solve for x first before you switch any variables. You dont do the inverse process until you solve for x in the original.
its 4y-4
x= 4y-4. This is your f(y). Now find the inverse of that.
thats the answer
Is that what it says?
Was I right the first time? o_O
@Luigi0210 yes you just needed the y i guess you have to change it back
I swear that makes no sense. Luigi did it correctly if it were f^-1(x), but it said f^-1(y) in thhe question. Whatever -_-
I got stumped on one of those before.. which is why I called my smart buddy over :3
Lol, her question is misleading then if none of that is a typo :/
yea i hate these ones they even confuse my teachers
Id say its written incorrectly.
no its correct its in my textbook to
Textbooks arent always correct, lol. I swear that doesnt make sense x_x Until someone I trust tells me no, lol.
Oh well, thats why you ask luigi and not me, lol.
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